document.write( "Question 320368: solve by elimination method\r
\n" ); document.write( "\n" ); document.write( "x+7y=23
\n" ); document.write( "-x+6y= 16 \n" ); document.write( "
Algebra.Com's Answer #229439 by Sunny Day(15)\"\" \"About 
You can put this solution on YOUR website!
Here you are given two equations and asked to find the value of x and y by eliminating one variable. On studying the two equations, we can see that 'x' has opposite signs in the two equations. So on adding the two equations, theyy will get eliminated and then you can solve for y.\r
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\n" ); document.write( "\n" ); document.write( "x+7y=23 ------------ (1)
\n" ); document.write( "-x+6y= 16 ------------ (2)
\n" ); document.write( "______________\r
\n" ); document.write( "\n" ); document.write( "Adding (1) and (2)\r
\n" ); document.write( "\n" ); document.write( "13y = 23 + 16
\n" ); document.write( "13y = 39\r
\n" ); document.write( "\n" ); document.write( "y = 39/13 = 3\r
\n" ); document.write( "\n" ); document.write( "Now put this value of y in either (1) or (2) to get the value of x.\r
\n" ); document.write( "\n" ); document.write( "ie. x + 7X3 = 23
\n" ); document.write( " x + 21 = 23
\n" ); document.write( " x = 23 - 21 = 2
\n" ); document.write( "So the solution in x = 2 and y = 3.\r
\n" ); document.write( "\n" ); document.write( "[cross- checking
\n" ); document.write( "Put x = @ and y = 3 in (2)\r
\n" ); document.write( "\n" ); document.write( "-2 + (6X3) = -2 + 18 = 16 which is the same as the given value.]\r
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