document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37258>Question 37258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this rational equation. I always have a problem on these ones when the denominators are like that. \r<BR>\n" );
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document.write( "(8/p+3) + (8/p-3) = -2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22942 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8/(p+3)+8/(p-3)=-2 or [8(p+3)+8(p-3)]/(p+3)(p-3)=-2 or\r<BR>\n" );
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document.write( "(8p+24+8p-24)/(p~2-9)=-2 or 16p/(p~2-9)=-2 or 16p=-2p~2+18 or 2p~2+16p-18=0 or\r<BR>\n" );
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document.write( "(2p-2)(p+9)=0 or p=1 & p=-9\r<BR>\n" );
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document.write( "proof 8/4+8/-2=-2 or 2-4=-2 or -2=-2 & 8/-6+8/-12=-2 or -4/3-2/3=-2 or -6/3=-2  </SPAN>\n" );
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