document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320318>Question 320318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3/5 is added to twice the reciprocal of a number, the result is 1. what is the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229412 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n = the number\r<BR>\n" );
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document.write( "(3/5) + 2(1/n) = 1\r<BR>\n" );
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document.write( "(3/5) + (2/n) = 1\r<BR>\n" );
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document.write( "5n * (3/5) + (2/n) * 5n = 1 * 5n\r<BR>\n" );
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document.write( "3n + 10 = 5n\r<BR>\n" );
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document.write( "10 = 5n - 3n\r<BR>\n" );
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document.write( "10 = 2n\r<BR>\n" );
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document.write( "10/2 = n\r<BR>\n" );
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document.write( "5 = n\r<BR>\n" );
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document.write( "Done! </SPAN>\n" );
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