document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320283>Question 320283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive page numbers is 60. Find the numbers.<BR>\n" );
document.write( "I dont understand what they mean can u help?   this problem was solved for me but i dont understand how the person  got the number 57 or the answer 19 can someone walk me through this i am so lost i would like to be able to work this out\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229389 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive page numbers is 60. Find the numbers.<BR>\n" );
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document.write( "Let the 1st page be \"x\"<BR>\n" );
document.write( "Next page is \"x+1\"<BR>\n" );
document.write( "Next page is \"x+2\"<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x + x+1 + x+2 = 60<BR>\n" );
document.write( "3x + 3 = 60<BR>\n" );
document.write( "3x = 57<BR>\n" );
document.write( "x = 19<BR>\n" );
document.write( "x+1 = 20<BR>\n" );
document.write( "x+2 = 21 <BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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