document.write( "Question 320175: The perimeter of a rectangle is 208 inches. The length exceeds the width by 54 inches. Find the length and the width \n" ); document.write( "

Algebra.Com's Answer #229343 by Sunny Day(15) $\"\"$ $\"About$

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if the length and width are represented by l and w respectively,
\n" ); document.write( " perimeter = 2(l+w) = 208 ------- (1)
\n" ); document.write( "length is greater than width by 54 inches.
\n" ); document.write( "So, l = 54 + w ------- (2)\r
\n" ); document.write( "\n" ); document.write( "Substituting for l in (1), we get\r
\n" ); document.write( "\n" ); document.write( "2(54 + w + w) = 208
\n" ); document.write( "2(54 + 2w) = 208
\n" ); document.write( "Removing the brackets,
\n" ); document.write( "2X54 + 2X2w = 208
\n" ); document.write( "108 + 4w = 208
\n" ); document.write( " 4w = 208 - 108
\n" ); document.write( " or 4w = 100
\n" ); document.write( " or w = 100/4 = 25\r
\n" ); document.write( "\n" ); document.write( "So l = 54 + w = 54 + 25 = 79\r
\n" ); document.write( "\n" ); document.write( "Hence length = 79 inches and width = 25 inches.\r
\n" ); document.write( "\n" ); document.write( "[On cross checking, you can see that the length is 54 inches greater than the width and that the perimeter is 208 inches] \n" ); document.write( "

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