document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37249>Question 37249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving this problem. I am confused on where to begin. The problem is 3x=6x+27. How would I go about solving this. I am horrible in Math and need your help. It is greatly appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22933 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x=6x+27\r<BR>\n" );
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document.write( "Adding (-6X) on both sides<BR>\n" );
document.write( "3X +(-6X) = 6X+27 +(-6X)<BR>\n" );
document.write( "-3X = 27<BR>\n" );
document.write( "Dividing by 3 on both sides<BR>\n" );
document.write( "X = -9 </SPAN>\n" );
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