document.write( "Question 320043: This one was a bit tricky for me, If anyone can help, I will greatly appreciate it. Here goes:
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document.write( "Demand for pools. Tropical Pools sells an aboveground
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document.write( "model for p dollars each. The monthly revenue for this
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document.write( "model is given by the formula
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document.write( "R(p)= -0.08p2 + 300p.
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document.write( "Revenue is the product of the price p and the demand
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document.write( "(quantity sold).
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document.write( "a) Factor out the price on the right-hand side of the
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document.write( "formula.
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document.write( "b) Write a formula D(p) for the monthly demand.
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document.write( "c) Find D(3000).
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document.write( "d) Use the accompanying graph to estimate the price at
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document.write( "which the revenue is maximized. Approximately how
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document.write( "many pools will be sold monthly at this price?
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document.write( "e) What is the approximate maximum revenue?
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document.write( "f) Use the accompanying graph to estimate the price at
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document.write( "which the revenue is zero
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document.write( "to solve each problem.\r
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document.write( "Price (dollars)
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document.write( "Revenue (thousands
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document.write( " 300\r
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document.write( " 200\r
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document.write( " 100\r
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document.write( " 0
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document.write( " 1000 2000 3000 4000\r
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document.write( " Price (dollars
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Algebra.Com's Answer #229290 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Demand for pools. Tropical Pools sells an above ground model for p dollars each. \n" ); document.write( "The monthly revenue for this model is given by the formula \n" ); document.write( "R(p)= -0.08p^2 + 300p. \n" ); document.write( ": \n" ); document.write( "Revenue is the product of the price p and the demand(quantity sold). \n" ); document.write( "; \n" ); document.write( "a) Factor out the price on the right-hand side of the formula. \n" ); document.write( "R(p)= p(-0.08p + 300). \n" ); document.write( ": \n" ); document.write( "b) Write a formula D(p) for the monthly demand. \n" ); document.write( "Demand is equal the revenue divided by the price \n" ); document.write( "D(p) = \n" ); document.write( "cancel p; \n" ); document.write( "D(p) = -.08p + 300 \n" ); document.write( ": \n" ); document.write( "c) Find D(3000). \n" ); document.write( "D(3000) = -.08(3000) + 300 \n" ); document.write( "D(3000) = -240 + 300 \n" ); document.write( "D(3000) = 60 pools when the price is $3000 \n" ); document.write( ": \n" ); document.write( "d) Use the accompanying graph to estimate the price at \n" ); document.write( "which the revenue is maximized. \n" ); document.write( " \n" ); document.write( "$1900 price for max revenue \n" ); document.write( ": \n" ); document.write( " Approximately how many pools will be sold monthly at this price? \n" ); document.write( "28000/1850 = 147 pools sold \n" ); document.write( ": \n" ); document.write( "e) What is the approximate maximum revenue? \n" ); document.write( "$280,000 \n" ); document.write( ": \n" ); document.write( "f) Use the accompanying graph to estimate the price at which the revenue is zero \n" ); document.write( "$3800 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |