document.write( "Question 320043: This one was a bit tricky for me, If anyone can help, I will greatly appreciate it. Here goes:
\n" ); document.write( "Demand for pools. Tropical Pools sells an aboveground
\n" ); document.write( "model for p dollars each. The monthly revenue for this
\n" ); document.write( "model is given by the formula
\n" ); document.write( "R(p)= -0.08p2 + 300p.
\n" ); document.write( "Revenue is the product of the price p and the demand
\n" ); document.write( "(quantity sold).
\n" ); document.write( "a) Factor out the price on the right-hand side of the
\n" ); document.write( "formula.
\n" ); document.write( "b) Write a formula D(p) for the monthly demand.
\n" ); document.write( "c) Find D(3000).
\n" ); document.write( "d) Use the accompanying graph to estimate the price at
\n" ); document.write( "which the revenue is maximized. Approximately how
\n" ); document.write( "many pools will be sold monthly at this price?
\n" ); document.write( "e) What is the approximate maximum revenue?
\n" ); document.write( "f) Use the accompanying graph to estimate the price at
\n" ); document.write( "which the revenue is zero
\n" ); document.write( "to solve each problem.\r
\n" ); document.write( "\n" ); document.write( "Price (dollars)
\n" ); document.write( "Revenue (thousands
\n" ); document.write( " 300\r
\n" ); document.write( "\n" ); document.write( " 200\r
\n" ); document.write( "\n" ); document.write( " 100\r
\n" ); document.write( "\n" ); document.write( " 0
\n" ); document.write( " 1000 2000 3000 4000\r
\n" ); document.write( "\n" ); document.write( " Price (dollars
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #229290 by ankor@dixie-net.com(22740)\"\" \"About 
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Demand for pools. Tropical Pools sells an above ground model for p dollars each.
\n" ); document.write( "The monthly revenue for this model is given by the formula
\n" ); document.write( "R(p)= -0.08p^2 + 300p.
\n" ); document.write( ":
\n" ); document.write( "Revenue is the product of the price p and the demand(quantity sold).
\n" ); document.write( ";
\n" ); document.write( "a) Factor out the price on the right-hand side of the formula.
\n" ); document.write( "R(p)= p(-0.08p + 300).
\n" ); document.write( ":
\n" ); document.write( "b) Write a formula D(p) for the monthly demand.
\n" ); document.write( "Demand is equal the revenue divided by the price
\n" ); document.write( "D(p) = \"p%28-.08p+%2B+300%29%2Fp\"
\n" ); document.write( "cancel p;
\n" ); document.write( "D(p) = -.08p + 300
\n" ); document.write( ":
\n" ); document.write( "c) Find D(3000).
\n" ); document.write( "D(3000) = -.08(3000) + 300
\n" ); document.write( "D(3000) = -240 + 300
\n" ); document.write( "D(3000) = 60 pools when the price is $3000
\n" ); document.write( ":
\n" ); document.write( "d) Use the accompanying graph to estimate the price at
\n" ); document.write( "which the revenue is maximized.
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-1000%2C+5000%2C+-50000%2C+400000%2C+-.08x%5E2%2B300x%29+\"
\n" ); document.write( "$1900 price for max revenue
\n" ); document.write( ":
\n" ); document.write( " Approximately how many pools will be sold monthly at this price?
\n" ); document.write( "28000/1850 = 147 pools sold
\n" ); document.write( ":
\n" ); document.write( "e) What is the approximate maximum revenue?
\n" ); document.write( "$280,000
\n" ); document.write( ":
\n" ); document.write( "f) Use the accompanying graph to estimate the price at which the revenue is zero
\n" ); document.write( "$3800
\n" ); document.write( ":
\n" ); document.write( "
\n" ); document.write( "
\n" );