document.write( "Question 320120: Find all zeros, both real and complex. x^3 + 3x^2 + 4x - 8.\r
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Algebra.Com's Answer #229263 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C++x%5E3+%2B+3x%5E2+%2B+4x-8%29\"
\n" ); document.write( "Looks like \"x=1\" is a zero.
\n" ); document.write( "Verify using the equation.
\n" ); document.write( "\"1%2B3%2B4-8=0\"
\n" ); document.write( "Yes, so \"x-1\" is a factor.
\n" ); document.write( "Use polynomial long division to find the remaining quadratic factor.
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\n" ); document.write( "First term: \"x%5E2\"
\n" ); document.write( "\"x%5E2%28x-1%29=x%5E3-x%5E2\"
\n" ); document.write( "Subtract from the original polynomial to get the remainder,
\n" ); document.write( "\"%28x%5E3%2B3x%5E2%2B4x-8%29-%28x%5E3-x%5E2%29=4x%5E2%2B4x-8\"
\n" ); document.write( "Next term: \"4x\"
\n" ); document.write( "\"4x%28x-1%29=4x%5E2-4x\"
\n" ); document.write( "Subtract from the first remainder to get the next remainder,
\n" ); document.write( "\"%284x%5E2%2B4x-8%29-%284x%5E2-4x%29=8x-8\"
\n" ); document.write( "Final term:\"8\"
\n" ); document.write( "\"8%28x-1%29=8x-8\"
\n" ); document.write( "Subtract from the second remainder to get the next remainder,
\n" ); document.write( "\"%288x-8%29-%288x-8%29=0\"
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\n" ); document.write( "\"%28x%5E3%2B3x%5E2%2B4x-8%29%2F%28x-1%29=x%5E2%2B4x%2B8\"
\n" ); document.write( "Solve for the remaining zeros by completing the square.
\n" ); document.write( "\"x%5E2%2B4x%2B8=0\"
\n" ); document.write( "\"x%5E2%2B4x%2B4%2B8-4=0\"
\n" ); document.write( "\"%28x%2B2%29%5E2%2B4=0\"
\n" ); document.write( "\"%28x%2B2%29%5E2=-4\"
\n" ); document.write( "\"x%2B2=0+%2B-+2i\"
\n" ); document.write( "\"highlight%28x=-2+%2B-+2i%29\"
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\n" ); document.write( "\"x=1\"
\n" ); document.write( "\"x=-2%2B2i\"
\n" ); document.write( "\"x=-2-2i\"
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