document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320080>Question 320080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y-3x=a<BR>\n" );
document.write( "3x-y=2<BR>\n" );
document.write( "what is a to make these equation a dependent system of linear equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229234 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y-3x=a<BR>\n" );
document.write( "3x-y=2<BR>\n" );
document.write( "what is a to make these equation a dependent system of linear equation<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Rearrange:<BR>\n" );
document.write( "y = 3x+a<BR>\n" );
document.write( "y = 3x-2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Ans: a = -2<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );