document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319973>Question 319973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A long distance trucker traveled 208 miles in one direction during a snow storm. The return trip in rainy weather was accomplished at double the speed and took 4 hours less. What was the speed going? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229201 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 208 miles in one direction during a snow storm. <BR>\n" );
document.write( "return trip double the speed and took 4 hours less. <BR>\n" );
document.write( "..<BR>\n" );
document.write( "let speed while going be xmph<BR>\n" );
document.write( "speed returning will be 2x mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time taken while going = 208/x<BR>\n" );
document.write( "time taken on return = 208/2x, 4 hours less<BR>\n" );
document.write( "208/x -4 = 208/2x\r<BR>\n" );
document.write( "\n" );
document.write( "208/x-208/2x= 4<BR>\n" );
document.write( "416-208 /2x=4<BR>\n" );
document.write( "208= 8x<BR>\n" );
document.write( "x=26 mph speed while going </SPAN>\n" );
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