document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4777>Question 4777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have two questions:<BR>\n" );
document.write( "1. The hieght of the Eiffel Tower is 984 feet. How long would it take an object to fall from the top?\r<BR>\n" );
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document.write( "2. The hypotenuse of a right triangle is 35 feet long. One leg is 7 feet longer than the other. Find the lengths of the legs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2292 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  Objects fall to earth at 32 feet per second. <BR>\n" );
document.write( "Distance/rate = time \r<BR>\n" );
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document.write( "984/32 = 30.75 seconds\r<BR>\n" );
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document.write( "2. Use the pythagorean theorem<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2++%2B+B%5E2+=+C%5E2 ALIGN=MIDDLE  ALT=\"A%5E2++%2B+B%5E2+=+C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "First Leg = A<BR>\n" );
document.write( "Second Leg = A+7<BR>\n" );
document.write( "Hypotenuse = 35\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2++%2B+%28A%2B7%29%5E2+=+35%5E2 ALIGN=MIDDLE  ALT=\"A%5E2++%2B+%28A%2B7%29%5E2+=+35%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Clear your parentheses:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2++%2B+%28A%5E2%2B14A%2B49%29+=+1225 ALIGN=MIDDLE  ALT=\"A%5E2++%2B+%28A%5E2%2B14A%2B49%29+=+1225\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Subtract 1225 from both sides to set the equation = to zero\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2A%5E2+%2B14A+%2B+-1176+=+0 ALIGN=MIDDLE  ALT=\"2A%5E2+%2B14A+%2B+-1176+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide the equation by two (factor out a two):<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2+%2B7A+%2B+-588+=+0 ALIGN=MIDDLE  ALT=\"A%5E2+%2B7A+%2B+-588+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Then use the quadratic equation to solve\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-7+%2B-+sqrt%28+49-4%2A1%2A-588+%29%29%2F%282%2A1%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-7+%2B-+sqrt%28+49-4%2A1%2A-588+%29%29%2F%282%2A1%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-7+%2B-+sqrt%28+49%2B2352+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-7+%2B-+sqrt%28+49%2B2352+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "Since we are talking about a measurement (a distance) we can disregard the negative answer,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-7+%2B+sqrt%28+2401%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-7+%2B+sqrt%28+2401%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 21 feet<BR>\n" );
document.write( "so the other leg is 28 feet \r<BR>\n" );
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