document.write( "Question 319985: You invested money in two funds. Last year, the first fund paid a dividend of 9% and the second a dividend of 3%, and you received 1047$. This year the first fund paid a 10% dividend and the second only 1% and you received a total of 846$. How much money did you invest in each fund? \n" ); document.write( "
Algebra.Com's Answer #229198 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let $x be invested in first fund \n" ); document.write( "let $y be invested in second fund\r \n" ); document.write( "\n" ); document.write( "first fund 9% \n" ); document.write( "the second 3%, \n" ); document.write( "received 1047$. \n" ); document.write( "Last year interest equation \n" ); document.write( "0.09x+0.03y=1047 \n" ); document.write( "multiply by 100 \n" ); document.write( "9x+3y=104700 ...... equation 1 \n" ); document.write( ".. \n" ); document.write( "This year first fund 10% \n" ); document.write( "second 1% \n" ); document.write( "received 846$. \n" ); document.write( "This year interest equation \n" ); document.write( "0.10x+0.01y=846 \n" ); document.write( "multiply by 100 \n" ); document.write( "10x+y=84600 ......... equation 2\r \n" ); document.write( "\n" ); document.write( "multiply equation 2 by 3 and subtract1 from it \n" ); document.write( "30x+3y-9x-3y=253800-104700 \n" ); document.write( "21x=149100 \n" ); document.write( "x= $ 7100 investment in first fund\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "10x+y=84600 substitute the value of x \n" ); document.write( "10*7100+y=84600 \n" ); document.write( "y=84600-71000 \n" ); document.write( "y= $ 13600 investment in second fund. \n" ); document.write( " |