document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319987>Question 319987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorist travels a distance of 120 miles.  Had she increased her average speed by 10 mi/hr she would have cut 36 minutes off of her travel time.  Find her average speed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229158 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let her speed be x<BR>\n" );
document.write( "increased speed = x+10<BR>\n" );
document.write( "distance traveled=120 miles<BR>\n" );
document.write( "36/60 = 3/5 hours<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time taken with increased speed= original time -3/5 hours<BR>\n" );
document.write( "120/x+10= 120/x  -3/5<BR>\n" );
document.write( "120/x+10=600-3x /5x<BR>\n" );
document.write( "5x*120=(x+10)(600-3x)<BR>\n" );
document.write( "600x=600x-30x+6000-3x^2<BR>\n" );
document.write( "3x^2+30x-6000=0<BR>\n" );
document.write( "x^2+10x-2000=0<BR>\n" );
document.write( "x^2+50x-40x-2000=0<BR>\n" );
document.write( "x(x+50)-40(x+50)=0<BR>\n" );
document.write( "(x+50)(x-40)=0<BR>\n" );
document.write( "x=40 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );