document.write( "Question 319945: 1. Find the area of the shaded segment of a circle with radius 10cm and central angle 45 degree.
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\n" ); document.write( "2. Solve the proportion:
\n" ); document.write( "\"h\"\"%22%3A%22\"\"10\"\"%22=%22\"\"1\"\"%22%3A%22\"\"sqrt%282%29\"
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Algebra.Com's Answer #229154 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "1. Find the area of the shaded segment of a circle with radius 10cm and central angle 45 degree.
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document.write( "That's the red area below:\r\n" );
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document.write( "The area of the sector A is to 45° as the area of the whole circle is to 360°:\r\n" );
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document.write( "The area of a whole circle is \r\n" );
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document.write( "\"A=pi%2Ar%5E2\"\"pi%2A10%5E2\"\"%22=%22\"\"100pi\"\r\n" );
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document.write( "So\r\n" );
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document.write( "\"A\"\"%22%3A%22\"\"%2245%22\"\"%22=%22\"\"100pi\"\"%22%3A%22\"\"360\"\r\n" );
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document.write( "\"A%2F45\"\"%22=%22\"\"%28100pi%29%2F360\"\r\n" );
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document.write( "Cross-multiply:\r\n" );
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document.write( "\"360A=4500pi\"\r\n" );
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document.write( "Divide both sides by 360\r\n" );
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document.write( "\"%28360A%29%2F360=%284500pi%29%2F360\"\r\n" );
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document.write( "\"A=%284500pi%29%2F360\"\r\n" );
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document.write( "\"A=25pi%2F2\"\r\n" );
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\n" ); document.write( "2. Solve the proportion:
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document.write( "\"h\"\"%22%3A%22\"\"10\"\"%22=%22\"\"1\"\"%22%3A%22\"\"sqrt%282%29\"\r\n" );
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document.write( "\"h%2F10\"\"%22=%22\"\"1%2Fsqrt%282%29\"\r\n" );
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document.write( "Cross-multiply:\r\n" );
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document.write( "\"sqrt%282%29%2Ah\"\"%22=%22\"\"10%2A1\"\r\n" );
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document.write( "\"sqrt%282%29%2Ah\"\"%22=%22\"\"10\"\r\n" );
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document.write( "Divide both sides by \"sqrt%282%29\"\r\n" );
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document.write( "\"%28sqrt%282%29%2Ah%29%2Fsqrt%282%29\"\"%22=%22\"\"10%2Fsqrt%282%29\"\r\n" );
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document.write( "Cancel on the left:\r\n" );
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document.write( "\"%28cross%28sqrt%282%29%29%2Ah%29%2Fcross%28sqrt%282%29%29\"\"%22=%22\"\"10%2Fsqrt%282%29\"\r\n" );
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document.write( "\"h\"\"%22=%22\"\"10%2Fsqrt%282%29\"\r\n" );
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document.write( "Rationalize the denominator on the right side by multiplying it by \"sqrt%282%29%2Fsqrt%282%29\"\r\n" );
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document.write( "\"h\"\"%22=%22\"\"10%2Fsqrt%282%29\"\"%22%D7%22\"\"sqrt%282%29%2Fsqrt%282%29\"\r\n" );
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document.write( "\"h\"\"%22=%22\"\"%2810sqrt%282%29%29%2F2\"\r\n" );
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document.write( "\"h\"\"%22=%22\"\"5sqrt%282%29\"\r\n" );
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document.write( "Edwin

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