document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319916>Question 319916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This one's been bugging me.\r<BR>\n" );
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document.write( "Find a linear function that satisfies both of the given conditions:\r<BR>\n" );
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document.write( "f(-1) = 1 + f(2) and f(3) = 4 * f(1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229117 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LINEAR ___ y = mx + b\r<BR>\n" );
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document.write( "\"f(-1) = 1 + f(2)\" ___ m(-1) + b = 1 + m(2) + b\r<BR>\n" );
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document.write( "subtracting b ___ -m = 1 + 2m ___ -1 = 3m ___ -1/3 = m\r<BR>\n" );
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document.write( "\"f(3) = 4 * f(1)\" ___ (-1/3)(3) + b = 4[(-1/3)(1) + b] ___ -1 + b = -4/3 + 4b\r<BR>\n" );
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document.write( "1/3 = 3b ___ 1/9 = b\r<BR>\n" );
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document.write( "y = (-1/3)x + 1/9 ___ 3x + 9y = 1 </SPAN>\n" );
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