document.write( "Question 319921: An airplane takes 9 hours to travel a distance of 6480km against the wind. The return trip takes 8 hours with the wind. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #229116 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "6,480=R9
\n" ); document.write( "R=6,480/9=720 KMH AGAINST THE WIND.
\n" ); document.write( "6,480=R8
\n" ); document.write( "R=6,480/8
\n" ); document.write( "R=810 KMH WITH THE WIND.
\n" ); document.write( "(810-720)/2=90/2=45 KMH IS THE SPEED OF THE WIND.
\n" ); document.write( "PROOF:
\n" ); document.write( "720+45=765 SPEED OF THE PLANE IN STILL AIR
\n" ); document.write( "810-45=765 DITTO.\r
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