document.write( "Question 319921: An airplane takes 9 hours to travel a distance of 6480km against the wind. The return trip takes 8 hours with the wind. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #229116 by checkley77(12844) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "6,480=R9 \n" ); document.write( "R=6,480/9=720 KMH AGAINST THE WIND. \n" ); document.write( "6,480=R8 \n" ); document.write( "R=6,480/8 \n" ); document.write( "R=810 KMH WITH THE WIND. \n" ); document.write( "(810-720)/2=90/2=45 KMH IS THE SPEED OF THE WIND. \n" ); document.write( "PROOF: \n" ); document.write( "720+45=765 SPEED OF THE PLANE IN STILL AIR \n" ); document.write( "810-45=765 DITTO.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |