document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319892>Question 319892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which is equivalent to 4 log3 a+3 log3(2b)-log3^m?\r<BR>\n" );
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document.write( "A)log3((2a^4b^3)/m)\r<BR>\n" );
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document.write( "B)log3((8a^4b^3)/m) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229102 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 log3 a+3 log3(2b)-log3^m?\r<BR>\n" );
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document.write( "Why did you include ^ in the term log3^m?  It makes no sense unless this is a typo.\r<BR>\n" );
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document.write( "I think you meant to type: 4log3(a) + 3log(2b) - log3(m).\r<BR>\n" );
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document.write( "In any case, several log rules must be applied here.\r<BR>\n" );
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document.write( "For 4log3(a) + 3log(2b), we apply logb(mn) = logb(m) + logb(n).  This is the multiplication of logs rule.\r<BR>\n" );
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document.write( "Then 4log3(a) + 3log(2b) becomes log3[(a^4*(2b)^3], which then becomes<BR>\n" );
document.write( "log3(8a^4*b^3).\r<BR>\n" );
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document.write( "We now have log3(8a^4*b^3) - log3(m) for which we apply <BR>\n" );
document.write( "logb(m/n) = logb(m) – logb(n). This is the division of logs rule.\r<BR>\n" );
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document.write( "Answer: log3[(8a^4*b^3)]/(m).\r<BR>\n" );
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document.write( "Copy and paste the following link to learn more about how to use the log rules:\r<BR>\n" );
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document.write( "http://www.purplemath.com/modules/logrules.htm\r<BR>\n" );
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document.write( " </SPAN>\n" );
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