document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319818>Question 319818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum. Express your answer in simplest form.\r<BR>\n" );
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document.write( "(14a^2 / 2b) + (3a / 2b)\r<BR>\n" );
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document.write( "a) 14a^2 + 3a / 4b<BR>\n" );
document.write( "b) 11a^2 /2b<BR>\n" );
document.write( "c) 14a^2 + 3a / 2b<BR>\n" );
document.write( "d) 11 / 2b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229051 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Why not use the rules for addition of regular fractions?  This is exactly what was given to you in algebraic form.\r<BR>\n" );
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document.write( "The denominator is the same for both fractions and so there is no need to find the LCD. We only need to find the LCD when the denominators are different or unlike.\r<BR>\n" );
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document.write( "(14a^2/2b) + (3a/2b) =\r<BR>\n" );
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document.write( "Keep the denominator and add the numerators.\r<BR>\n" );
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document.write( "Answer is: (14a^2 + 3a)/(2a), which is choice c.\r<BR>\n" );
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