document.write( "Question 319800: Find the coordinates of the center of the circle and length of the radius given the equation of that circle which is \"5x%5E2%2B15x%2B5y%5E2-10y-10=0\" \n" ); document.write( "
Algebra.Com's Answer #229049 by Edwin McCravy(20055)\"\" \"About 
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\"5x%5E2%2B15x%2B5y%5E2-10y-10=0\"
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document.write( "We need to get it in the form \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" so we'll\r\n" );
document.write( "know it has center (h,k) and radius r.\r\n" );
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document.write( "First we add 10 to both sides to get the constant off the left side:\r\n" );
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document.write( "\"5x%5E2%2B15x%2B5y%5E2-10y=10\"\r\n" );
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document.write( "Next we divide through by the common coefficient of x² and y² which\r\n" );
document.write( "is 5\r\n" );
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document.write( "\"5x%5E2%2F5%2B15x%2F5%2B5y%5E2%2F5-10y%2F5=10%2F5\"\r\n" );
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document.write( "\"x%5E2%2B3x%2By%5E2-2y=2\"\r\n" );
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document.write( "Put the addition of one blank after the 3x and another after the -2y since we\r\n" );
document.write( "are going to add something to both sides\r\n" );
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document.write( "\"x%5E2%2B3x%2B%22__%22%2By%5E2-2y%2B%22__%22=2\"\r\n" );
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document.write( "Next we calculate what goes in the first blank:\r\n" );
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document.write( "1. Multiply the coefficient of x, which is 3, by \"1%2F2\"}, getting \"3%2F2\"\r\n" );
document.write( "2. Square that value:  \"%283%2F2%29%5E2+=+9%2F4\", so \"red%289%2F4%29\" is what goes\r\n" );
document.write( "in the first blank, and we also add it to the right side:\r\n" );
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document.write( "\"x%5E2%2B3x%2Bred%289%2F4%29%2By%5E2-2y%2B%22__%22=2%2Bred%289%2F4%29\"  \r\n" );
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document.write( "Next we calculate what goes in the second blank:\r\n" );
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document.write( "1. Multiply the coefficient of y, which is -2, by \"1%2F2\"}, getting \"-1\"\r\n" );
document.write( "2. Square that value:  \"%28-1%29%5E2+=+%22%2B1%22\", so \"red%281%29\" is what goes\r\n" );
document.write( "in the second blank, and we also add it to the right side:\r\n" );
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document.write( "\"x%5E2%2B3x%2Bred%289%2F4%29%2By%5E2-2y%2Bred%281%29=2%2Bred%289%2F4%29%2Bred%281%29\"\r\n" );
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document.write( "The first three terms on the left \"x%5E2%2B3x%2B9%2F4\" factors as \"%28x%2B3%2F2%29%28x%2B3%2F2%29\" or \"%28x%2B3%2F2%29%5E2\"\r\n" );
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document.write( "The last three terms on the left \"y%5E2-2y%2B1\" factors as \"%28y-1%29%28y-1%29\" or \"%28y-1%29%5E2\"\r\n" );
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document.write( "The right side \"2%2B9%2F4%2B1\" becones \"8%2F4%2B9%2F4%2B4%2F4=21%2F4\"\r\n" );
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document.write( "So we now have:\r\n" );
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document.write( "\"%28x%2B3%2F2%29%5E2%2B%28y-1%29%5E2=21%2F4\"\r\n" );
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document.write( "And we compare that to \r\n" );
document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" \r\n" );
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document.write( "and we see that since \"-h=%22%22%2B3%2F2%22\", \"h=-3%2F2\", and\r\n" );
document.write( "since \"-k=-1\", \"k=1\". Also \"r%5E2=21%2F4\" so \"r=sqrt%2821%29%2F2\"}\r\n" );
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document.write( "Edwin
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