document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319727>Question 319727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider an equation of direct variation y=kx. When x increases, does y increase or decrease? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228987 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Are we forcing 'k' to be positive? If so, then as x increases, then y increases. On the other hand, if 'k' is negative, then as x increases, then y decreases(eg, k=-2, x=1 and y=-2 compared to x=3 and y=-6). If we let k be any real number (other than zero), then we can't determine what y does when x goes up. </SPAN>\n" );
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