document.write( "Question 319713: Man is five times older than his son. Four years ago he was nine times older than his son. Find thier present ages. \n" ); document.write( "
Algebra.Com's Answer #228966 by mananth(16949) You can put this solution on YOUR website! let son be x years \n" ); document.write( "father =5x\r \n" ); document.write( "\n" ); document.write( "five years ago their ages were \n" ); document.write( "x-5 & 5x-5 \n" ); document.write( "5x-5=9(x-5) \n" ); document.write( "5x-5=9x-45 \n" ); document.write( "4x=40 \n" ); document.write( "x=10 years ---- son's age \n" ); document.write( "Father's age = 50 years \n" ); document.write( " |