document.write( "Question 319713: Man is five times older than his son. Four years ago he was nine times older than his son. Find thier present ages. \n" ); document.write( "
Algebra.Com's Answer #228966 by mananth(16949)\"\" \"About 
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let son be x years
\n" ); document.write( "father =5x\r
\n" ); document.write( "\n" ); document.write( "five years ago their ages were
\n" ); document.write( "x-5 & 5x-5
\n" ); document.write( "5x-5=9(x-5)
\n" ); document.write( "5x-5=9x-45
\n" ); document.write( "4x=40
\n" ); document.write( "x=10 years ---- son's age
\n" ); document.write( "Father's age = 50 years
\n" ); document.write( "
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