document.write( "Question 319702: Solve using the multiplication principle.
\n" ); document.write( " -x/5 ≥ 2
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Algebra.Com's Answer #228948 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"-x%2F5%3E=2\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"cross%285%29%28-x%2Fcross%285%29%29%3E=5%282%29\" Multiply both sides by 5.\r
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\n" ); document.write( "\n" ); document.write( "\"-1x%3E=10\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=%2810%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=-10\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x%3C=-10\"
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