document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37074>Question 37074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem involving positive exponents.\r<BR>\n" );
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document.write( "The problem is a fraction problem with negative exponents that are then raised to another negative exponent.   Y^-7 divided by Y^-2 to the -2^. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22893 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you mean [y^(-7) / y^(-2)] ^ (-2), we do it this way...<BR>\n" );
document.write( "Apply the rules for dividing like bases and subtract exponents...thus within the square brackets you get <BR>\n" );
document.write( "[y^(-7--2)]^(-2) =<BR>\n" );
document.write( "[y^(-5)]^(-2)<BR>\n" );
document.write( "Now applying the power rule, you multiply exponents and get<BR>\n" );
document.write( "y^10 </SPAN>\n" );
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