document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319690>Question 319690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle's width is one-fifth its length, and its perimeter is 144m. Find the dimenision of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228925 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L/5<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "144=2L+2(L/5)<BR>\n" );
document.write( "144=2L+2L/5 FIND THE LCD (5)<BR>\n" );
document.write( "144=(5*2L+2L)/5<BR>\n" );
document.write( "144=(10L+2L)/5 CROSS MULTIPLY<BR>\n" );
document.write( "10L+2L=144*5<BR>\n" );
document.write( "12L=720<BR>\n" );
document.write( "L=720/12<BR>\n" );
document.write( "L=60 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "W=60/5=12 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "144=2*60+2*12<BR>\n" );
document.write( "144=120+24<BR>\n" );
document.write( "144=144\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );