document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37197>Question 37197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help Me Again!!Thanks For The Other Help,too!<BR>\n" );
document.write( "5x=4y-7<BR>\n" );
document.write( "4x=5y-2<BR>\n" );
document.write( "        thank you!!!!!!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22892 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 5x = 4y - 7 and 4x = 5y - 2, we will have to multiply the first equation by 4 and the second equation by 5, which gives us<BR>\n" );
document.write( "20x = 16y - 28<BR>\n" );
document.write( "20x = 25y - 10<BR>\n" );
document.write( "The idea is to subtract these equations so that one variable is eliminated.  When we subtract them, we get<BR>\n" );
document.write( "0 = -9y - 18  and<BR>\n" );
document.write( "y = -2<BR>\n" );
document.write( "Plugging that value in above, you get<BR>\n" );
document.write( "5x = 4(-2) - 7<BR>\n" );
document.write( "5x = -15<BR>\n" );
document.write( "x = -3 </SPAN>\n" );
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