document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37196>Question 37196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Larry is three times as old as Moe, and Curly is sixteen years younger than Larry, Larry's age was twice the sum of the ages of Moe and Curly. Find each man's age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22891 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, this one works out kind of funny, but it works out.  First, write the equations from the info given.  Thus we have<BR>\n" );
document.write( "L = 3M<BR>\n" );
document.write( "C = L - 16<BR>\n" );
document.write( "L = 2(M + C)<BR>\n" );
document.write( "Now substitute into that third equation values for M and C to get<BR>\n" );
document.write( "L = 2[(L/3) + (L - 16)]<BR>\n" );
document.write( "L = (8/3)L - 32  and<BR>\n" );
document.write( "(-5/3)L = -32  so that<BR>\n" );
document.write( "L = 96/5 = 19.2 yrs  From that<BR>\n" );
document.write( "C = 16/5 = 3.2 yrs   and<BR>\n" );
document.write( "M = 32/5 = 6.4 yrs </SPAN>\n" );
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