document.write( "Question 319627: Each side of a rectangle increased by l%. The perimeter of the rectangle is
\n" ); document.write( "increased by\r
\n" ); document.write( "\n" ); document.write( "a 4% b 2% c 1% d 0.25% e 0.5%
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Algebra.Com's Answer #228893 by Alan3354(69443)\"\" \"About 
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Each side of a rectangle increased by l%. The perimeter of the rectangle is
\n" ); document.write( "increased by
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\n" ); document.write( "Let x=width
\n" ); document.write( "and y=length
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\n" ); document.write( "Original perimeter is
\n" ); document.write( "2(x+y)
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\n" ); document.write( "Increased by 1%
\n" ); document.write( "1.01x = width
\n" ); document.write( "1.01y = lenth
\n" ); document.write( "perimeter is:
\n" ); document.write( "2(1.01x + 1.01y)
\n" ); document.write( "2*1.01(x+y)
\n" ); document.write( "2.02(x+y)
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\n" ); document.write( "amount increased:
\n" ); document.write( "2.02(x+y) - 2(x+y)
\n" ); document.write( "(x+y)(2.02-2)
\n" ); document.write( "(x+y)(0.02)
\n" ); document.write( "0.02(x+y)
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\n" ); document.write( "percent increased is then
\n" ); document.write( "[.02(x+y)]/[2(x+y)] * 100
\n" ); document.write( "[.02]/[2] * 100
\n" ); document.write( ".01 * 100
\n" ); document.write( "1%
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\n" ); document.write( "I copied and pasted Nerdy Bill's solution, and changed it from 10% to the requested 1%.
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\n" ); document.write( "Nerdy Bill used 10% increase (inadvertently) and got a 10% increase in perimeter. I used 1%, and got a 1% increase in perimeter.
\n" ); document.write( "The perimeter is linearly related to the side lengths. s*x --> p*x
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