document.write( "Question 319627: Each side of a rectangle increased by l%. The perimeter of the rectangle is
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document.write( "a 4% b 2% c 1% d 0.25% e 0.5% \n" );
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Algebra.Com's Answer #228890 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Each side of a rectangle increased by l%. The perimeter of the rectangle is \n" ); document.write( "increased by \n" ); document.write( ". \n" ); document.write( "Let x=width \n" ); document.write( "and y=length \n" ); document.write( ". \n" ); document.write( "Original perimeter is \n" ); document.write( "2(x+y) \n" ); document.write( ". \n" ); document.write( "Increased by 1% \n" ); document.write( "1.1x = width \n" ); document.write( "1.1y = lenth \n" ); document.write( "perimeter is: \n" ); document.write( "2(1.1x + 1.1y) \n" ); document.write( "2*1.1(x+y) \n" ); document.write( "2.2(x+y) \n" ); document.write( ". \n" ); document.write( "amount increased: \n" ); document.write( "2.2(x+y) - 2(x+y) \n" ); document.write( "(x+y)(2.2-2) \n" ); document.write( "(x+y)(0.2) \n" ); document.write( ".2(x+y) \n" ); document.write( ". \n" ); document.write( "percent increased is then \n" ); document.write( "[.2(x+y)]/[2(x+y)] * 100 \n" ); document.write( "[.2]/[2] * 100 \n" ); document.write( ".1 * 100 \n" ); document.write( "10% \n" ); document.write( " \n" ); document.write( " |