document.write( "Question 37195: how do solve x square root3= square root 12 \n" ); document.write( "
Algebra.Com's Answer #22889 by ilana(307)![]() ![]() ![]() You can put this solution on YOUR website! well sqrt12=sqrt4*sqrt3, so x=sqrt4=2. \n" ); document.write( "We also could have said x=sqrt12/sqrt3, so x=sqrt(12/3), so x=sqrt4=2. \n" ); document.write( "So x=2. \n" ); document.write( " |