document.write( "Question 37195: how do solve x square root3= square root 12 \n" ); document.write( "
Algebra.Com's Answer #22889 by ilana(307)\"\" \"About 
You can put this solution on YOUR website!
well sqrt12=sqrt4*sqrt3, so x=sqrt4=2.
\n" ); document.write( "We also could have said x=sqrt12/sqrt3, so x=sqrt(12/3), so x=sqrt4=2.
\n" ); document.write( "So x=2.
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