document.write( "Question 319605: find y so that x^2+(y+1)x+y+4=0 has only one solution (i am not asking you to solve the quadratic in terms of y) \n" ); document.write( "
Algebra.Com's Answer #228871 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint: The quadratic equation \"ax%5E2%2Bbx%2Bc=0\" has only one solution if \"b%5E2-4ac=0\"\r
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\n" ); document.write( "\n" ); document.write( "In this case, \"a=1\", \"b=y%2B1\", and \"c=y%2B4\". Plug this all into the second equation provided above to get \"%28y%2B1%29%5E2-4%281%29%28y%2B4%29=0\". Simply solve this new equation to find the value(s) of 'y' that make \"x%5E2%2B%28y%2B1%29x%2By%2B4=0\" have only one solution.
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