document.write( "Question 319570: solve each system of equations algebraically
\n" ); document.write( "1/x + 3/y = 6
\n" ); document.write( "2/x -1/y = 1 \n" ); document.write( "

Algebra.Com's Answer #228857 by stanbon(75887) $\"\"$ $\"About$

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solve each system of equations algebraically
\n" ); document.write( "1/x + 3/y = 6
\n" ); document.write( "2/x -1/y = 1
\n" ); document.write( "-------------
\n" ); document.write( "Let 1/x = a
\n" ); document.write( "Let 1/y = b
\n" ); document.write( "------
\n" ); document.write( "Rewrite the equations:
\n" ); document.write( "a + 3b = 6
\n" ); document.write( "2a - b = 1
\n" ); document.write( "-------------
\n" ); document.write( "Multiply thru 1st equation by 2 to get:
\n" ); document.write( "2a + 6b = 12
\n" ); document.write( "2a - b = 1
\n" ); document.write( "------------------
\n" ); document.write( "Subtract 2nd from 1st and solve for \"b:
\n" ); document.write( "7b = 11
\n" ); document.write( "b = 11/7
\n" ); document.write( "---------------------------
\n" ); document.write( "Since a = 6-3b, a = 6-33/7 = 9/7
\n" ); document.write( "--------
\n" ); document.write( "Since a = 1/x, x = 7/9
\n" ); document.write( "Since b = 1/y, y = 7/11
\n" ); document.write( "==========================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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