document.write( "Question 319453: Soybean meal is 18% protein; cornmeal is 9% protein. How many pounds of each should be mixed together in order to get 360-lb mixture that is 11% protein?\r
\n" );
document.write( "\n" );
document.write( "How many pounds of the cornmeal should be in the mixture?
\n" );
document.write( "How many pounds of the soybean meal should be in the mixture? \n" );
document.write( "
Algebra.Com's Answer #228854 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Soybean meal is 18% protein; cornmeal is 9% protein. \n" ); document.write( " How many pounds of each should be mixed together in order to get 360-lb mixture that is 11% protein? \n" ); document.write( ": \n" ); document.write( "Let x = amt of Soy \n" ); document.write( "the result is to be 360 lb, therefore \n" ); document.write( "(360-x) = amt of corn \n" ); document.write( ": \n" ); document.write( "An amt of protein equation \n" ); document.write( ".18x + .09(360-x) = .11(360) \n" ); document.write( ": \n" ); document.write( ".18x + 32.4 - .09x = 39.6 \n" ); document.write( ": \n" ); document.write( ".18x - .09x = 39.6 - 32.4 \n" ); document.write( ": \n" ); document.write( ".09x = 7.2 \n" ); document.write( "x = \n" ); document.write( "x = 80 lb of soy \n" ); document.write( "and \n" ); document.write( "360 - 80 = 280 lb of corn \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original mixture equation \n" ); document.write( ".18(80) + .09(280) = .11(360) \n" ); document.write( "14.4 + 25.2 = 39.6, confirms our solution \n" ); document.write( " |