document.write( "Question 37082This question is from textbook Geometry-reasoning applying measuring
\n" ); document.write( ": I have a hexagon and its side lengths are of 14cm, and it has a circular bulls eye right in the muddle with a diameter of 3cm. what is the probability that the dart that hits the target will hit the bulls eye?\r
\n" ); document.write( "\n" ); document.write( "Also it asks to estimate how many times a dart will the bulls eye if 100 darts hit the target? \n" ); document.write( "

Algebra.Com's Answer #22883 by fractalier(6550) $\"\"$ $\"About$

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The question asks you to compare the area of the circular bullseye to the area of the hexagon. The area of the hexagon is found by A = 1/2(a)(p) where a is the apothem and p is the perimeter. The apothem can be found by looking at the height of the equilateral traingles that make up a regular hexagon. It is 7 radical 3. So the hexagon's area is
\n" ); document.write( "A = (1/2)(7 radical 3)(84) = 294 radical 3 or about 509.2 sq cm.
\n" ); document.write( "The area of the bullseye is
\n" ); document.write( "A = (pi)r^2 = (1/4)(pi)d^2 = (9/4)(pi) or about 7.065 sq cm.\r
\n" ); document.write( "\n" ); document.write( "By dividing the two areas, we get 1.387% chance of hitting a bullseye if the arrows hit the target randomly. That means 1.387 arrows per hundred hit the bullseye. \n" ); document.write( "

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