document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37191>Question 37191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi all,\r<BR>\n" );
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document.write( "I need some help with school study work. I need to solve this quadratic equation by using the square root property?<BR>\n" );
document.write( "1: 4x^2 - 48= 0\r<BR>\n" );
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document.write( "2: I need to solve this quadratic equation by completing square?<BR>\n" );
document.write( "x^2 + 24 = -10x\r<BR>\n" );
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document.write( "Anyone, please help me  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22882 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from 4x^2 - 48 = 0, we add 48 to both sides and then divide by four, giving us x^2 = 12.  Take the root of both sides to give x = ± radical 12 = ± 2 radical 3.  <BR>\n" );
document.write( "The second problem, x^2 + 24 = -10x, requires us to move the -10x to the left side and the 24 to the right to get<BR>\n" );
document.write( "x^2 + 10x = -24    <BR>\n" );
document.write( "Now we take half of the 10 and square it to get 25.  That is what we add to both sides and get<BR>\n" );
document.write( "x^2 + 10x + 25 = 1<BR>\n" );
document.write( "(x + 5)^2 = 1<BR>\n" );
document.write( "x + 5 = ±1<BR>\n" );
document.write( "x = -5 ± 1 = -6 or -4 </SPAN>\n" );
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