document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37189>Question 37189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> it's me again... not sure as to what i did wrong on this one.\r<BR>\n" );
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document.write( "the directions are to give the coordinates of the point where each line crosses the y-axis. y = -3x\r<BR>\n" );
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document.write( "my answer: (-3,0) (o,1) do you mind helping with this one? thanx!! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22879 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When a line crosses the y-axis, its x-value is zero.  Merely plug x = 0 into y = -3x and find that y = 0 too.  So it goes thru (0, 0). </SPAN>\n" );
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