document.write( "Question 319494: Let A be the ratio of the volume of a sphere to the volume of a cube each of whose face is tangent to the sphere, and let B be the ratio of the surface area of this sphere to the surface area of the cube. Then find the sum A and B. \n" ); document.write( "
Algebra.Com's Answer #228781 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let A be the ratio of the volume of a sphere to the volume of a cube each of \n" ); document.write( " whose face is tangent to the sphere, and let B be the ratio of the surface \n" ); document.write( " area of this sphere to the surface area of the cube. \n" ); document.write( " Then find the sum A and B. \n" ); document.write( ": \n" ); document.write( "From the description, the sphere is enclosed in a cube \n" ); document.write( ": \n" ); document.write( "Let r = radius of the sphere \n" ); document.write( "then \n" ); document.write( "2r = side of the cube \n" ); document.write( ": \n" ); document.write( "Volume Ratio; sphere/cube \n" ); document.write( "A = \n" ); document.write( "cancel r^3 \n" ); document.write( "A = \n" ); document.write( ": \n" ); document.write( "Surface area ratio; sphere/cube \n" ); document.write( "B = \n" ); document.write( "Cancel 4, and r^2 \n" ); document.write( "B = \n" ); document.write( ": \n" ); document.write( "A + B: \n" ); document.write( " \n" ); document.write( " |