document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319429>Question 319429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 4 less than twice its length. If the area of the rectangle is 177 cm^2, what is the length of the diagonal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228746 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length be x<BR>\n" );
document.write( "width = 2x-4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area =177 cm^2<BR>\n" );
document.write( "x(2x-4)=177<BR>\n" );
document.write( "2x^2-4x-177=0<BR>\n" );
document.write( "roots of the equation x1 x2 are<BR>\n" );
document.write( "x1= -(-4)+sqrt(16+4*2*177) / 2*2<BR>\n" );
document.write( "x1=10.46<BR>\n" );
document.write( "x2= -(-4)-sqrt(16+4*2*177) / 2*2<BR>\n" );
document.write( "x2=-8.46\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "length = 10.46cm<BR>\n" );
document.write( "width = 16.92cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );