document.write( "Question 319403: Eliminate 0(theta)between the equation
\n" ); document.write( "q tan 0(theta) + p sec 0(theta)=x
\n" ); document.write( "p tan 0(theta) + q sec 0(theta)=y \n" ); document.write( "

Algebra.Com's Answer #228720 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Eliminate 0(theta)between the equation
\n" ); document.write( "q tan(theta) + p sec(theta)=x
\n" ); document.write( "p tan(theta) + q sec(theta)=y
\n" ); document.write( "------
\n" ); document.write( "Rearrange:
\n" ); document.write( "q tan(theta) + p sec(theta)=x
\n" ); document.write( "q sec(theta) + p tan(theta)=y
\n" ); document.write( "--------------
\n" ); document.write( "Multiply thru the 1st equation by sec(theta)
\n" ); document.write( "Multiply thru the 2nd equation by tan(theta)
\n" ); document.write( "---
\n" ); document.write( "q(sec)(tan) + p sec^2 = x*sec
\n" ); document.write( "q(sec)(tan) + p tan^2 = y*tan
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Subtract the 2nd equation from the 1st to get:
\n" ); document.write( "p(sec^2-tan^2) = x*sec-y*tan
\n" ); document.write( "---
\n" ); document.write( "Note sec^2-tan^2 = 1
\n" ); document.write( "---
\n" ); document.write( "p = x*sec-y*tan
\n" ); document.write( "----------------------
\n" ); document.write( "Substitute for \"p\" and solve for \"q\".
\n" ); document.write( "========================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "========================================
\n" ); document.write( " \n" ); document.write( "

\n" );