document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37098>Question 37098</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SOS! I really need help here. thank you very much.\r<BR>\n" );
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document.write( "convert to logarithmic equations. For example, the logarithmic form of \"23 = 8\" is \"log2 8 = 3\".   \r<BR>\n" );
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document.write( "16 3/2 = 64 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22870 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16^(3/2) = 64<BR>\n" );
document.write( "(16^(1/2))^3 = 64<BR>\n" );
document.write( "4^3 = 64<BR>\n" );
document.write( "(2^2)^3 = 64<BR>\n" );
document.write( "2^6 = 64<BR>\n" );
document.write( "log(base 2)64 = 6<BR>\n" );
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