document.write( "Question 319371: What is the probability of getting between 3 and 6 heads in 10 tosses of a fair coin? \n" ); document.write( "
Algebra.Com's Answer #228689 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"between 3 and 6\" is ambiguous. Do you mean inclusive or exclusive of 3 and 6? No matter, I'll show you what to do either way.\r
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\n" ); document.write( "\n" ); document.write( "If you mean inclusive of 3 and 6, then the probability you seek is the probability of getting exactly 3 heads out of 10 tosses, plus the probability of getting exactly 4, plus exactly 5, plus exactly 6.\r
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\n" ); document.write( "\n" ); document.write( "On the other hand, if you mean exclusive, then the probability you seek is the probability of exactly 4 heads out of 10 tosses plus the probability of exactly 5 heads out of 10 tosses.\r
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\n" ); document.write( "\n" ); document.write( "The probability of successes out of trials where the probability of success on any individual trial is is given by:\r
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\n" ); document.write( "\n" ); document.write( "Where is the number of combinations of things taken at a time and has the value \r
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\n" ); document.write( "\n" ); document.write( "For a fair coin toss, the probability of a head on any given trial is \r
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\n" ); document.write( "\n" ); document.write( "So, for the inclusive case, you need to calculate the following:\r
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\n" ); document.write( "\n" ); document.write( "And sum the four results.\r
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\n" ); document.write( "\n" ); document.write( "For the exclusive case, you only need to compute\r
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\n" ); document.write( "\n" ); document.write( "and sum the two results\r
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