document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319367>Question 319367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a comma to separate answers as needed, unless it is not a real number\r<BR>\n" );
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document.write( "Solve: The square root of 5x + 29 = x + 3\r<BR>\n" );
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document.write( "Thanks so much!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228683 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt{5x + 29} = x + 3\r<BR>\n" );
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document.write( "Square both sides to begin. By squaring both sides, you will then be able to remove the radical from the left side.\r<BR>\n" );
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document.write( "[sqrt{5x + 29}]^2 = (x + 3)^2\r<BR>\n" );
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document.write( "5x + 29 = x^2 + 6x + 9\r<BR>\n" );
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document.write( "0 = x^2 + 6x - 5x + 9 - 29\r<BR>\n" );
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document.write( "0 = x^2 + x - 20\r<BR>\n" );
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document.write( "0 = (x - 4)(x + 5)\r<BR>\n" );
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document.write( "Set each factor to zero and solve for x.\r<BR>\n" );
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document.write( "x - 4 = 0\r<BR>\n" );
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document.write( "x = 4\r<BR>\n" );
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document.write( "OR\r<BR>\n" );
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document.write( "x + 5 = 0\r<BR>\n" );
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document.write( "x = -5\r<BR>\n" );
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document.write( "To make sure that x = 4 and x = -5 are correct, plug those two values for x into the original radical equation given.  The correct x value will produce the same answer on both sides of the equation after simplifying.  I'll let you do that, however.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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