document.write( "Question 37169This question is from textbook Algebra 1
\n" ); document.write( ": Factor. Check by using FOIL or the distributive property.
\n" ); document.write( "m^3 + 6m^2 + 9m
\n" ); document.write( "and then a question not from the book, b^2-6b-10, factor this one also please.
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Algebra.Com's Answer #22867 by jcmtnez(53)\"\" \"About 
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(1) Here is the first
\n" ); document.write( "m^3+6m^2+9m=0 , This polynomial of degree 3 is divisible by m, therefore we divede by m and get:\r
\n" ); document.write( "\n" ); document.write( "m(m^2+6m+9)=0 Now we have to solve the polynomial of degree two, and the solution is m=-3, and is unique. Finally we get\r
\n" ); document.write( "\n" ); document.write( "m(m+3)(m+3) As the factorization of m^3 + 6m^2 + 9m \r
\n" ); document.write( "\n" ); document.write( "(2) Here is the second
\n" ); document.write( "b^2-6b-10=0, First have to solve the equation, find the roots, we can do this using the general formula or using more advance methods. Using the formula we get as a result b=3+sqrt(19), and b=3-sqrt(19). Then the factors will be\r
\n" ); document.write( "\n" ); document.write( "(b-(3-sqrt(19))(b-(3+(sqrt(19)) \r
\n" ); document.write( "\n" ); document.write( "\"b%5E2-6b-10=%28b-%283-sqrt%2819%29%29%29%28b-%283%2Bsqrt%2819%29%29%29\"\r
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