document.write( "Question 319320: please help me find this. A rectangle has an area of 12 square inches and a perimeter of 16 square inches. Find the length and width of the rectangle. Show your work. \n" ); document.write( "
Algebra.Com's Answer #228627 by stanbon(75887)\"\" \"About 
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please help me find this. A rectangle has an area of 12 square inches and a perimeter of 16 square inches. Find the length and width of the rectangle. Show your work.
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\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "Area = length*width
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\n" ); document.write( "Equations:
\n" ); document.write( "L + W = 8
\n" ); document.write( "LW = 12
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\n" ); document.write( "Solve by substitution:
\n" ); document.write( "L = 8-W
\n" ); document.write( "---
\n" ); document.write( "Substitute for \"L\" in the 2nd equation and solve for \"W\":
\n" ); document.write( "(8-W)W = 12
\n" ); document.write( "8W-W^2 = 12
\n" ); document.write( "---
\n" ); document.write( "Rearrange:
\n" ); document.write( "W^2 - 8W +12 = 0
\n" ); document.write( "---
\n" ); document.write( "Factor:
\n" ); document.write( "(W-6)(W-2) = 0
\n" ); document.write( "---
\n" ); document.write( "If W = 6, L = 2
\n" ); document.write( "If W = 2, L = 6
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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