document.write( "Question 319172: a passenger train leaves a train depot three hours after a freight train leaves the same depot. the freight train is traveling 8 mph slower than the passenger train. find the rate of the passenger train if the passenger train overtakes the freight train after 12.75 h \n" ); document.write( "

Algebra.Com's Answer #228596 by nyc_function(2741) $\"\"$ $\"About$

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You know that at the moment they meet, they've traveled the same distance, so you'll set the distances equal to each other for each train. Remember that rate(time) = distance. \r
\n" ); document.write( "\n" ); document.write( "Let x = rate of passenger train\r
\n" ); document.write( "\n" ); document.write( "Passenger train: x(12.75)
\n" ); document.write( "Freight train: (x-6)(15.75)\r
\n" ); document.write( "\n" ); document.write( "12.75x = 15.75x - 94.5; x = 31.5 mph
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