document.write( "Question 319190: Samia walks for a time at 4mph, then slows down and walks at 3.2mph. The total distance she walked was 6 miles. If she walked for 0.5 hour more at 3.2 mph than she did at 4mph, determine the time Samia walked at 4mph. \n" ); document.write( "
Algebra.Com's Answer #228566 by ankor@dixie-net.com(22740)\"\" \"About 
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Samia walks for a time at 4mph, then slows down and walks at 3.2mph.
\n" ); document.write( " The total distance she walked was 6 miles.
\n" ); document.write( " If she walked for 0.5 hour more at 3.2 mph than she did at 4mph,
\n" ); document.write( " determine the time Samia walked at 4mph.
\n" ); document.write( ":
\n" ); document.write( "Let t = time walked at 4 mph
\n" ); document.write( "then
\n" ); document.write( "(t+.5) = time walked at 3.2 mph
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\n" ); document.write( "Write a distance equation: dist = speed * time
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\n" ); document.write( "dist at 4 + dist at 3.2 = 6 miles
\n" ); document.write( "4t + 3.2(t+.5) = 6
\n" ); document.write( ":
\n" ); document.write( "4t + 3.2t + 1.6 = 6
\n" ); document.write( ":
\n" ); document.write( "7.2t = 6 - 1.6
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\n" ); document.write( "7.2t = 4.4
\n" ); document.write( "t = \"4.4%2F7.2\"
\n" ); document.write( "t = .611 hrs at 4 mph
\n" ); document.write( "and
\n" ); document.write( ".611 + .5 = 1.111 hrs at 3.2 mph
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\n" ); document.write( "Check solution by finding the distances
\n" ); document.write( ".611 * 4 = 2.44 mi
\n" ); document.write( "1.11 * 3.2 = 3.55 mi
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\n" ); document.write( "total dist: 5.99 ~ 6 mi
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