document.write( "Question 318891: A production filling operation has a population standard deviation of 6 ounces. When in proper adjustment, the mean filling weight for the production process is 50 ounces. A quality control inspector selects a random sample of 36 containers and finds that the mean weight is 48.6 ounces. Does the process need adjustment? Why? Find the p-value. (Hint: the process will need adjustment if the mean weight is either significantly above or below 50 ounces) \n" ); document.write( "
Algebra.Com's Answer #228546 by stanbon(75887) ![]() You can put this solution on YOUR website! A production filling operation has a population standard deviation of 6 ounces. \n" ); document.write( "----------- \n" ); document.write( "When in proper adjustment, the mean filling weight for the production process is 50 ounces. \n" ); document.write( "----------------- \n" ); document.write( "A quality control inspector selects a random sample of 36 containers and finds that the mean weight is 48.6 ounces. \n" ); document.write( "----------------- \n" ); document.write( "Does the process need adjustment? Why? Find the p-value. (Hint: the process will need adjustment if the mean weight is either significantly above or below 50 ounces) \n" ); document.write( "---- \n" ); document.write( "Ho: u = 50 ounces \n" ); document.write( "Ha: u is not equal to 50 ounces \n" ); document.write( "------------------ \n" ); document.write( "x-bar = 48.6 ounces \n" ); document.write( "--- \n" ); document.write( "t(48.6) = (48.6-50)/[6/sqrt(36)] = -1.4 \n" ); document.write( "---- \n" ); document.write( "p-value = 2*P(t< -1.4 when df = 35) = 0.1703 \n" ); document.write( "----- \n" ); document.write( "Since the p-value is greater than 5%, fail to reject Ho. \n" ); document.write( "The mean of the production process is statistically equal to 50; \n" ); document.write( "it does not need adjustment. \n" ); document.write( "========================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |