document.write( "Question 319156: A lake is stocked with 496 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 3100.The population of fish in the lake after time t, in months, is given by the function, P(t) =3100/1 + 5.7e^-0.28t. After how many months will the population be 1289? \n" ); document.write( "
Algebra.Com's Answer #228541 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Let P(t) = 1289\r \n" ); document.write( "\n" ); document.write( "Here is your equation:\r \n" ); document.write( "\n" ); document.write( "1289 = 3100 + 5.7e^(-0.28t)\r \n" ); document.write( "\n" ); document.write( "Can you take it from here? \n" ); document.write( " |