document.write( "Question 319109: please help me solve this problem: A rocket is fired straight up from the ground at a time t= 0 with an initial speed of 560 feet per second. The rocket's distance of h feet above the ground t seconds later h=560t-16t^2 At what time will the rocket be 3, 136 feet above the ground? \n" ); document.write( "
Algebra.Com's Answer #228515 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The more general formula is:\r
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\n" ); document.write( "\n" ); document.write( "Where is the height as a function of time, , is the initial velocity, and is the initial height.\r
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\n" ); document.write( "\n" ); document.write( "For your problem the rocket was launched from the ground so , and fps.\r
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\n" ); document.write( "\n" ); document.write( "We need to know the value of that makes feet.\r
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\n" ); document.write( "\n" ); document.write( "Divide through by \r
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\n" ); document.write( "\n" ); document.write( "This quadratic factors quite neatly, yielding two positive roots. I'll leave it as an exercise for the student to figure out the significance of two answers, both apparently valid.\r
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