document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37162>Question 37162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a/b is a fraction. If 2 is added to the numerator, the value of the fraction is 1/2. I f 3 is added to the denominator, the fraction has a value of 1/3. What is the value of the sum a+b?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22846 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem can be solved by substitution because you have two unknowns and two equations.\r<BR>\n" );
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document.write( "Solve the first equation for b:<BR>\n" );
document.write( "a+2/b = 1/2<BR>\n" );
document.write( "2a+4 = b\r<BR>\n" );
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document.write( "Substitute the found value for b into the second equation:<BR>\n" );
document.write( "a/b+3 = 1/3<BR>\n" );
document.write( "a/2a+4+3 = 1/3<BR>\n" );
document.write( "3a = 2a + 7<BR>\n" );
document.write( "a = 7\r<BR>\n" );
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document.write( "Now substitute the found value for a into the first equation:<BR>\n" );
document.write( "2a+4 = b<BR>\n" );
document.write( "2(7)+4 = b<BR>\n" );
document.write( "18 = b\r<BR>\n" );
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document.write( "a+b = 7+18 = 25 </SPAN>\n" );
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