document.write( "Question 36086This question is from textbook Working with Numbers Algebra
\n" ); document.write( ": The sum of 5 and a negative integer is greater than -4 and less than 0. How many possible negative intergers satisfy the information? \n" ); document.write( "
Algebra.Com's Answer #22843 by jcmtnez(53)\"\" \"About 
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-4<5+x<0 and x<0 Because it is negative\r
\n" ); document.write( "\n" ); document.write( "-4=5+x
\n" ); document.write( "-9=x Therefore x must be greater than -9 \r
\n" ); document.write( "\n" ); document.write( "5+x=0
\n" ); document.write( "x=-5 Therefore x must be less than -5\r
\n" ); document.write( "\n" ); document.write( " The solution of the problem is the open interval of the numbers greater than -9 and less than -5, S=(-6,-7,-8) Are the threes negative integers that are solution to the problem.
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